Linear Algebra
Math · Advanced · Lesson 3 of 7

Inverses & Systems

Solving equations with matrices

An interactive lesson with 6 steps, about 5 minutes: you predict, drag and solve, with instant feedback on every answer. It runs in your browser and needs JavaScript.

What you’ll learn

  • A system of equations is Ax=bA\mathbf x = \mathbf b, solved by x=A−1b\mathbf x = A^{-1}\mathbf b.
  • 2×22 \times 2 inverse: swap aa and dd, negate bb and cc, divide by ad−bcad - bc.
  • det⁡A=0\det A = 0 means no inverse, and either no solution or infinitely many.

Steps

  1. Two lines
  2. The same system as a matrix
  3. Compute an inverse
  4. When there is no inverse
  5. Solve a system
  6. Find the bad value